SOLUTION: can someone help me solve this?? �(x) = (x4)/4 − 3x3 + (23x2)/2 - 15x Find the x values where the extremes occur. A. 1, -3, 5 B. 1, 3, -5 C. 1, 3, 5 D. 1, -3

Question 1028960: can someone help me solve this??
�(x) = (x4)/4 − 3x3 + (23x2)/2 - 15x
Find the x values where the extremes occur.

A. 1, -3, 5
B. 1, 3, -5
C. 1, 3, 5
D. 1, -3, -5
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
using calculus and taking the derivative
x^3-9x^2+23x-15=0
Test each.
1 works, and it does for all choices
for 5, 125-225+115-15=0, so 5 works.
for 3, 27-81+69-15=0
It is C.

RELATED QUESTIONS
Can someone help me on this?? I'm stuck �(x) = (x^4)/4 − 3x^3 + (23x^2)/2 - 15x (answered by Fombitz)

Can someone please help me with a couple of problems on polynomials finding the quotient... (answered by Edwin McCravy)

I am having difficulty factoring (x^4 - 1). The following is my attempt, will someone... (answered by helpnalgebra,jim_thompson5910)

Evaluate each polynomial for x = 3 and for x = −3. the question is... −x2... (answered by solver91311)

I am having difficulty factoring (x^16 - 1). The following is my attempt, will someone... (answered by Earlsdon)

Can you help me solve this 3x3 equation: 2x+y-z=3 2x+2y-z=-1... (answered by richwmiller,stanbon)

find the relative maximum and relative minimum values of the function below.... (answered by RAY100)

I have to solve the problem 3/4(x-2)-2/5(2x-3)=1/5, can someone please help me solve... (answered by jim_thompson5910)

Can someone please help me solve this problem? 2/5x+5 - 3/x^2-1 =... (answered by jsmallt9)

SOLUTION: can someone help me solve this?? �(x) = (x4)/4 &#8722; 3x3 + (23x2)/2 - 15x Find the x values where the extremes occur. A. 1, -3, 5 B. 1, 3, -5 C. 1, 3, 5 D. 1, -3

SOLUTION: can someone help me solve this?? �(x) = (x4)/4 − 3x3 + (23x2)/2 - 15x Find the x values where the extremes occur. A. 1, -3, 5 B. 1, 3, -5 C. 1, 3, 5 D. 1, -3