SOLUTION: can someone help answer these twin questions?? they don't make any sense, thanks #1 Factor the expression on the left side of the equation. Then solve the equation. x3 −

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Question 1028785: can someone help answer these twin questions?? they don't make any sense, thanks
#1 Factor the expression on the left side of the equation. Then solve the equation.
x3 − 2x2 − 5x = 0

A. 0, -1 +/- sqrt 24
B. -5, 0, 3
C. 0, 1 +/- sqrt 6
D. 0, -1 +/- sqrt 6
#2 Factor the expression on the left side of the equation. Then solve the equation.
x6 + 128x3 + 4096 = 0

A. 4, 2 +/- 2i*sqrt 3
B. 4 multiplicity of 2, 2 +/- 2i*sqrt3 multiplicity of 2
C. -4, 2 +/- 2i*sqrt 3
D. - 4 multiplicity of 2, 2 +/- 2i*sqrt3 multiplicity of 2

Answer by ikleyn(52776)   (Show Source): You can put this solution on YOUR website!
.
#1 Factor the expression on the left side of the equation. Then solve the equation.
x^3 - 2x^2 - 5x = 0

A. 0, -1 +/- sqrt 24
B. -5, 0, 3
C. 0, 1 +/- sqrt 6
D. 0, -1 +/- sqrt 6
~~~~~~~~~~~~~~~~~~~~~

Factor:

 = .

Solve the equation  = . Apply the quadratic formula

 =  =  =  = .

The roots of the original equation are  0,    and  .

The answer is option C.

#2 Factor the expression on the left side of the equation. Then solve the equation.
x6 + 128x3 + 4096 = 0
A. 4, 2 +/- 2i*sqrt 3
B. 4 multiplicity of 2, 2 +/- 2i*sqrt3 multiplicity of 2
C. -4, 2 +/- 2i*sqrt 3
D. - 4 multiplicity of 2, 2 +/- 2i*sqrt3 multiplicity of 2

Factor

 = .   (1)

Now solve  

 = .        (2)

It is reduced to 

 = ,         (3)

 = ,

 = ,  ,  ,   or, which is the same 

,  ,  ,   or,  which is the same again

,  .     (4).


Thus the solution of (3) are the roots (4).

Hence, the solution of (1) are the roots listed under the option D)


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