SOLUTION: The directions say "Solve each equation" Here are the problems: 1. x to the fourth=49 2.x to the fourth-6x²=-8 3.x to the fourth-3x²=54 4.3t to the sixth-48t²=0 5.m to th

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Question 1027324: The directions say "Solve each equation"
Here are the problems:
1. x to the fourth=49
2.x to the fourth-6x²=-8
3.x to the fourth-3x²=54
4.3t to the sixth-48t²=0
5.m to the sixth-16m³+64=0
6.y to the fourth-5y²+4=0
7. x to the fourth-29x²+100=0
8.4x to the fourth-73x²+144=0

Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
a. x= +/- sqrt (7)
b. x^4-6x^2+8=0;(x^2-4)(x^2-2)=0; x= +/-2, and +/- sqrt (2)
c.x^4-3x^2-54=0; (x^2-9)(x^2+6)=0; x=+/-3; +/- i sqrt (6)
d. 3t^2(t^4-16)=0; t=0, -2,+2
e.m^6-16m^3+64=0;(m^3-8)(m^3-8)=0, m=2
f.y^4-5y^2+4=0; (y^2-4)(y^2-1)=0; y=-2,-1,1,2
g.x^4-29x^2+100=0; (x^2-25)(x^2-4)=0; x=-5,+5,-2,+2
h.4 x^4-73x^2+144=0; (x^2-16)(4x^2-9)=0;x=-4, +4, -(3/2),+(3/2)
Treat them all as quadratics then put x^2 as the first term and not x and solve, getting two roots for each parenthetical term.

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