SOLUTION: How do I factor (10x^2 + 23x + 12) The sum of the factors of 12 is not 23x.

Algebra.Com
Question 1021426: How do I factor (10x^2 + 23x + 12)
The sum of the factors of 12 is not 23x.

Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!






Answer by MathTherapy(10555)   (Show Source): You can put this solution on YOUR website!
How do I factor (10x^2 + 23x + 12)
The sum of the factors of 12 is not 23x.
Apparently, you're trying to use the "ac" method.
It's the factors of 120, not 12 that are supposed to SUM to + 23x. These factors are + 15x and + 8x.
RELATED QUESTIONS

How to factor completely 10x^2 + 23x +... (answered by jim_thompson5910,lenny460)
I need to find all the factors of the polynomial: 3x^3+20x^2+23x-10. I already know that... (answered by richwmiller)
{{{20x^2+23x+12}}} (answered by Alan3354,stanbon)
Factor completely 10x^4 - 11x^3 + 23x^2 + 23x -... (answered by stanbon)
Please solve the equation using the zero-factor property. Thank you... (answered by checkley75)
Please help me to solve this equation using the zero-factor property.... (answered by stanbon)
what is the discriminant of 20x^2-23x-6 (answered by josgarithmetic)
please help with this polynomial 10x^2+23x+12... (answered by jim_thompson5910)
Hello, I am having trouble with using Synthetic division to find the remaining factors (answered by longjonsilver)