SOLUTION: factor:8x^3-27
Algebra.Com
Question 1009363: factor:8x^3-27
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
factor:8x^3-27
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The form is "the difference of cubes".
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(2x)^3 - 3^3 = (2x-3)((2x)^2 + 2x*3 + 3^2)
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= (2x-3)(4x^2 + 6x + 9)
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Cheers,
Stan H.
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