SOLUTION: Convert the equation to polar form. (Use variables r and θ as needed.)
y = 2x^2
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Question 1009005: Convert the equation to polar form. (Use variables r and θ as needed.)
y = 2x^2
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
For y = 2x^2, we use
y = r sin θ and
x = r cos θ to get
r sin θ = 2(r cos θ)^2
r sin θ = 2r^2(cos θ)^2
sin θ = 2r(cos θ)^2 so that
r = sin θ / 2(cos θ)^2
which can also be expressed in terms of tan and sec...
r = (1/2)sec θ tan θ
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