SOLUTION: The length of a rectangle is 3 ft less than double the width, and the area of the rectangle is 44 ft squared. Find the dimensions of the rectangle.
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Question 1007052: The length of a rectangle is 3 ft less than double the width, and the area of the rectangle is 44 ft squared. Find the dimensions of the rectangle.
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Call the length and width, L and W.
We then have
L = 2W - 3 and
A = area = LW = 44
Substituting in we have
(2W - 3)W = 44
2W^2 - 3W - 44 = 0
(2W - 11)(W + 4) = 0
and
2W = 11
W = 5.5 feet
L = 2(5.5) - 3 = 8 feet
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