SOLUTION: zeros of -3,1, and 4;f(2)=30 a=-3 b=1 c=4 f(x)=(x+3)(x-1)(x-4)

SOLUTION: zeros of -3,1, and 4;f(2)=30 a=-3 b=1 c=4 f(x)=(x+3)(x-1)(x-4)

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Question 1002917: zeros of -3,1, and 4;f(2)=30

a=-3 b=1 c=4
f(x)=(x+3)(x-1)(x-4)
Answer by ikleyn(52777) (Show Source): You can put this solution on YOUR website!
.
zeros of -3,1, and 4;f(2)=30

a=-3 b=1 c=4
f(x)=(x+3)(x-1)(x-4)
----------------------------------

f(2) = (2+3)*(2-1)*(2-4) = 5*1*(-2) = -10.

So, apply the factor (-3) to f(x):

F(x) = -3*f(x).

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