SOLUTION: If one-half of one integer is subtracted from three-fifths of the next consecutive integer, the difference is 3. What are the two integers? My initial response is: 3/5x-1/2x+1

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: If one-half of one integer is subtracted from three-fifths of the next consecutive integer, the difference is 3. What are the two integers? My initial response is: 3/5x-1/2x+1      Log On


   

Question 100063: If one-half of one integer is subtracted from three-fifths of the next consecutive integer, the difference is 3. What are the two integers?
My initial response is: 3/5x-1/2x+1=3. I know its wrong but I can't find any help in this text book.
Found 2 solutions by edjones, scott8148:
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
let the integers be: x, x+1
%283%2F5%29%28x%2B1%29-%281%2F2%29x=3
Multiply 10 times each side: 6(x+1)-5x=30
6x+6-5x=30
x+6=30
subtract 6 from each side: x=24
x+1=25
Check:
(3/5)25-(1/2)24=3
15-12=3
Ed

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
your equation is slightly garbled

one-half of one integer ... x/2

is subtracted from three-fifths of the next consecutive integer ... 3/5(x+1)-(x/2)

the difference is 3 ... (3x/5)+(3/5)-(x/2)=3

multiplying by 10 gives 6x+6-5x=30 ... x=24 ... x+1=25