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Tutors Answer Your Questions about Polynomials-and-rational-expressions (FREE)
Question 241299: Can someone show me how to complete this problem..I have tried to look it up but can not figure it out.
Add
(2s^4-3s^3+4s^2+14s-9)+(s^5+9s^3+5s^2-4s+5)+(-5a^4+s^2-6s-7)
Answer by unlockmath(117)   (Show Source):
You can put this solution on YOUR website!Hello,
We need to combine like terms. Like terms in this problem are the ones that have the same power and base.
(2s^4-3s^3+4s^2+14s-9)+(s^5+9s^3+5s^2-4s+5)+(-5a^4+s^2-6s-7)
Here's how it would look:
(s^5+2s^4+6s^3+10s^2+4s-11)-5a^4 (Note: check to make sure you copied the -5a^4 correctly. If it's supposed to be -5s^4 then it can be added to +2s^4 which would make it -3s^4)
RJ Toftness
www.math-unlock.com
Question 240383: Driving time. The time t required to drive a fixed distance varies inversely as the speed r. It takes 5 hr at 55mph to drive a fixed distance. How long wold it take at 40mph?
Answer by Alan3354(6079)  (Show Source):
You can put this solution on YOUR website!The time t required to drive a fixed distance varies inversely as the speed r. It takes 5 hr at 55mph to drive a fixed distance. How long wold it take at 40mph?
---------------
5*55 = 275 miles
275 mi/40 mph = 6.857 hours
Question 241298: I am completely lost and would like the step by step play so I can understand what to do.
Subtract the polynomials (-5v^2+6v+3)-(8v^2+3)=
Answer by ankor@dixie-net.com(6693)  (Show Source):
You can put this solution on YOUR website! (-5v^2+6v+3)-(8v^2+3) =
remove the brackets,
remember, if there is a minus outside the brackets, you change all the signs inside the brackets
-5v^2 + 6v + 3 - 8v^2 - 3 =
:
group like terms
-5v^2 - 8v^2 + 6v + 3 - 3 =
:
Combine like terms
-13v^2 + 6v
Question 241297: I need help factoring 28-11t+t^2. I would be grateful for the help.
Answer by Theo(675)  (Show Source):
You can put this solution on YOUR website!equation is:
t^2 - 11t + 28
4*7 = 28 and 4+7 = 11 so that's a good candidate.
make your factors (x-7) * (x-4) and you should be ok.
multiply the factors out to double check.
(x-7) * (x-4) =
x^2 - 4x - 7x + 28
combine like terms to get:
x^2 - 11x + 28
looks ok.
should be your answer.
I used x instead of t, but the concept is the same.
replace my x with your t and you'll be good to go.
Question 241229: could you please help me factor
27m^8-90m^6+45m^4
Answer by rapaljer(3620)  (Show Source):
You can put this solution on YOUR website!27m^8-90m^6+45m^4
The first step in ANY factoring problem is to take out the COMMON FACTOR. In this case, it would be 9m^4:
9m^4(3m^4 -10m^2 + 5)
The resulting trinomial does not seem to factor
I have a LOT of resources on my own website on the topic of FACTORING. To find my website, do a "BING" or a "GOOGLE" search for my last name "Rapalje". Near the top of the search list, you should see "Rapalje Homepage." Click on this, and look near the top of my homepage for the link "Basic, Intermediate and College Algebra: One Step at a Time." Choose "Basic Algebra", and look in "Chapter 2" for various sections on factoring, especially "Section 2.03, Factoring the Common Factor." This is my own explanation especially written for students who have trouble understanding math. I wrote this to students, NOT mathematicians, and I think you will find it easier to understand than your own traditional textbooks!! In addition to this page, the entire website is supported by my "MATH IN LIVING COLOR" pages, where the hardest problems are solved IN COLOR.
In addition, I have a video of me teaching this topic in the classroom a few years ago. To see this FREE video, from my Homepage, look for "Rapalje Videos in Living Color". Select "Basic Algebra", and look for "FACTORING."
If you like my website, please recommend it to family and friends who have trouble understanding math!! It's ALL FREE!!!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Question 241270: a^4 - ab^3 =
I am not sure how you solve this polynomial? Can someone explain the steps on how to work this problem?
Thanks.
Answer by rapaljer(3620) (Show Source):
You can put this solution on YOUR website!This is a FACTORING problem. The first step in any factoring problem is to take out the COMMON FACTOR. In this case, the common factor is a
a^4-ab^3
a(a^3-b^3)
This is a DIFFERENCE of CUBES, which requires a special formula that is actually the product of a BINOMIAL times a TRINOMIAL.
a(______)(_________)
The binomial is the first, which is "a" minus the second, which is "b":
a(a-b)(___________)
The trinomial consists of the square of the first, PLUS the product of the first times the second, plus the square of the second.
a(a-b)(a^2+ab+b^2)
I have a LOT of resources on my own website on the topic of FACTORING. To find my website, do a "BING" or a "GOOGLE" search for my last name "Rapalje". Near the top of the search list, you should see "Rapalje Homepage." Click on this, and look near the top of my homepage for the link "Basic, Intermediate and College Algebra: One Step at a Time." Choose "Intermediate Algebra", and look in "Chapter 2" for "Section 2.01, Factoring." Select the Section called "Sum and Difference of Cubes." It's a topic that you probably will need more help with than other topics. This is my own explanation especially written for students who have trouble understanding math. I wrote this to students, NOT mathematicians, and I think you will find it easier to understand than your own traditional textbooks!! In addition to this page, the entire website is supported by my "MATH IN LIVING COLOR" pages, where the hardest problems are solved IN COLOR.
In addition, I have a video of me teaching this topic in the classroom a few years ago. To see this FREE video, from my Homepage, look for "Rapalje Videos in Living Color". Select "Intermediate Algebra", and look for "Factoring". You don't have to watch the whole video, which is over an hour long, but instead you can fast forward the video so you can see the topic that you need help with.
If you like my website, please recommend it to family and friends who have trouble understanding math!! It's ALL FREE!!!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Question 241272: Perform the indicated operation.Write each answer in lowest terms.
m^2 - 1/(m - 1)^2 * 2m - 2/3m + 3 =
I am having problems understanding how to perform the indicated operation. Can someone explain to me the steps I am supposed to use and how to solve this problem?
Answer by rapaljer(3620) (Show Source):
You can put this solution on YOUR website!Do you mean this?
If this is it, then factor everything that you can:
Divide out the (m+1) factors and all the (m-1) factors, and what is left over is  .
I have a chapter on fractions on my own website. To find my website, do a "BING" or a "GOOGLE" search for my last name "Rapalje". Near the top of the search list, you should see "Rapalje Homepage." Click on this, and look near the top of my homepage for the link "Basic, Intermediate and College Algebra: One Step at a Time." Choose "Basic Algebra", and look in "Chapter 3" for "Section 3.02, Multiplying and Dividing Fractions." This is my own explanation especially written for students who have trouble understanding math. I wrote this to students, NOT mathematicians, and I think you will find it easier to understand than your own traditional textbooks!! In addition to this page, the entire website is supported by my "MATH IN LIVING COLOR" pages, where the hardest problems are solved IN COLOR.
If you like my website, please recommend it to family and friends who have trouble understanding math!! It's ALL FREE!!!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Question 240343: The length of a rectangular frame is 6 cm more than the width. The area inside the frame is 55 square cm. Find the width of the frame.
Answer by College Student(210)  (Show Source):
You can put this solution on YOUR website!The formula for the area of a rectangle is: Area = width*lenght
.
Let width = x
and lenght = x + 6
Area = 55 square cm
.
 or 
.
Check:
.
.
*** Even though both numbers check, the width of a rectangle (or its lenght for that matter) must be a positive number, so we choose ***
Question 241261: n(3) = -(3 t^2+1) (t-8). find n
Answer by stanbon(26268) (Show Source):
Question 241256: I am having a hard time even trying to set this problem up, I am sure once i see how to set it up I will be able to solve it.
the sum of a number and 36 times its reciprocal is -13. Find the number.
Please any help would be appreciated,
thanks,
heather
Answer by jim_thompson5910(13787) (Show Source):
You can put this solution on YOUR website!Remember the sum of two numbers is simply the result of adding them. So the sum of x and y is  . In this particular problem, the first addend is the unknown number 'x' and the second addend is 36 times its reciprocal. In other words, the second number is 
So add these two expressions to get:  and set that equal to -13 to get 
I'll let you take it from here. All you need to do now is solve for 'x'.
Question 240341: what does it mean when it asks for me to give the degree of the answer? my answer is -7x+x2+17
Answer by Alan3354(6079) (Show Source):
You can put this solution on YOUR website!what does it mean when it asks for me to give the degree of the answer? my answer is -7x+x2+17
--------
If it's  , then it's of degree 2, or 2nd degree, or 2nd order, all terms meaning the same thing.
2 is the highest exponent in the expression.
Question 241242: Okay, I'm lost on this one, I've tried it a few different ways and my program keeps telling me I have the wrong answer. Any suggestions?
Factor a quadratic polynomial in two variables.
2x^2+7xy-15y^2
Thanks so much for any help!
Answer by checkley77(7049) (Show Source):
Question 241220: Perform the indicated operations and simplify.
x^2/3x^2-5x-2-2x/3x+1∙1/(x-2)
Found 2 solutions by jsmallt9, stanbon:
Answer by jsmallt9(590) (Show Source):
You can put this solution on YOUR website!(Note: A solution provided by another tutor has some very serious errors in it. The solution is not correct. The first part was correct. You do want to factor the denominators, use the factored denominators to find the lcd and you do want to write each fraction with the lcd for the denominator. But after that it goes very wrong. This is where I will start.)
lcd: 
To avoid some common errors with subtractions, I am going to rewrite the expression as additions:
The first fraction already has the lcd as a denominator. The denominator of the second fraction is missing (x-2) so we will multiply its numerator and denominator by (x-2). The denominator of the third fraction is missing (3x+1) so we will multiply its numerator and denominator by (3x+1):
Multiply out the numerators but leave the denominators factored for now:
Now that the denominators are the same we can add:
At this point we should try to reduce the fraction. To reduce the fraction we have to factor the numerator and denominator. (We didn't multiply out the denominator earlier so that we would not have to factor it again now.) The only factoring that can be done on the numerator, however, is to factor out a -1:
As we can see, there are no common factors to cancel. So all we can do is simplify (i.e. multiply out):
Answer by stanbon(26268) (Show Source):
You can put this solution on YOUR website!Perform the indicated operations and simplify.
[x^2/3x^2-5x-2]-[2x/3x+1]∙[1/(x-2)]
-----------------------------
Factor where you can:
[x^2/(x-2)(3x+1]-[2x/3x+1]∙[1/(x-2)]
---
lcd = (x-2)(3x+1)
---------------------------
Write each fraction with the lcd as its denominator:
[x^2/lcd] - [2x/lcd]
----
Combine the numerators over the lcd:
(x^2-2x]/[(x-2)(3x+1)]
---
(x(x-2))/[(x-2)(3x+1)]
---
x/(3x+1)
=================
Cheers,
Stan H.
Question 241131: Solve. (This one is really hard!)
3a-5/a^2+4a+3 + 2a+2/a+3 = a-3/a+1
Answer by ankor@dixie-net.com(6693) (Show Source):
You can put this solution on YOUR website! +  = 
do some factoring here
 +  =
The common denominator is (a+3)(a+1) multiply thru by this
:
(a+3)(a+1)* + (a+3)(a+1)* = (a+3)(a+1)*
:
Cancel out the denominators, leaving:
(3a - 5) + (a+1)*2(a+1) = (a+3)(a-3)
:
FOIL
3a - 5 + 2(a^2 + 2a+ 1) = a^2 + 3a - 3a - 9
:
3a - 5 + 2a^2 + 4a + 2 = a^2 - 9
:
combine like terms on the left
2a^2 - a^2 + 3a + 4a - 5 + 2 + 9 = 0
:
a^2 + 7a + 6 = 0
Factor
(a + 6)(a + 1) = 0
Two solutions
a = -6
a = -1
;
:
Check in original equation using x=-6
 +  = 
 +  = 
 + =
 +  =  ; confirms our solution
;
:
You can check it using x=-1
Question 241180: a decorator plans to place a rug in a room 9m by 12m in such a way that a uniform strip of flooring around the rug will remain uncovered. if the rug is to cover half the floor space, what should the dimensions of the rug be?
Answer by solver91311(5072)  (Show Source):
Question 241098: 8x^4-27x+16x^3-54 I need help factoring this :-)
Answer by jsmallt9(590) (Show Source):
You can put this solution on YOUR website!There are a variety of factoring techniques: - Greatest Common Factor (GCF)
- Patterns
- Difference of Squares:
 - Difference of Cubes:
 - Sum of Cubes:
 - Perfect Trinomial Squares:
- Trinomial factoring
 - Factoring by grouping
- Factoring by trial and error of the possible rational roots
Always start with GCF factoring. After that, be ready to use any of the other techniques in any order and possibly using some of them repeatedly.
The GCF of this expression is 1 and this is the only GCF we do not often factor out. Next I would look at factoring by grouping because - There are 4 terms which is too many for any of the patterns or for trinomial factoring.
- The odd order of the terms is possibly a clue that factoring by grouping should be done.
- Factoring by trial and error of the possible rational roots looks like it would be tedious because of the large number of possible rational roots.
When factoring by grouping you factor GCF's from pairs (or sets) of terms. (Note: This is one of the rare times where you do factor out a GCF that is one!)
Now, if we are lucky, the "other" factors (i.e. the factors that were not the GCF of the pair, the ones in red) in each group are the same. And as you can see, we are lucky. The  's are the same. (If these "other factors" did not match, then we would start over, rearrange the terms and try again. If you run out of rearrangements and never get matching "other factors" then the expression will not factor with this technique.)
Now we factor out the matching "other factors". This is perhaps the most difficult step to learn when factoring by grouping so I have color-coded the before and after expressions so you can see where things were and where they end up:
When you reduce fractions you always reduce them until you can reduce them any further. Factoring is like this, too. Always keep factoring until you can't factor any more.
Since  and  , the first factor fits the "Difference of Cubes" pattern which we can use to factor it. (The last factor, (x+2), will not factor further.)
which simplifies to:
The first factor will not factor further. The second factor looks like it might be factorable. But, as long as you have already factored out the GCF of the entire expression (which you should have done before anything else), then the second factor from the Difference (or Sum) of Cubes is inherently unfactorable. If you know this then you will know not to waste time trying.
Since none of the factors will factor any further we are finished!
Question 241092: Can someone help me with this one and show the work? Thanks
(a^2-21)/(a-5)
Answer by Alan3354(6079) (Show Source):
Question 241103: please help me with factoring- 16x^4y-y^5
Answer by vleith(1977) (Show Source):
Question 241088: The time t required to drive a fixed distance varies inversely as the speed r. It takes 5 hrs at 55 mph to drive a fixed distance. How long would it take at 40 mph?
Answer by nyc_function(260)  (Show Source):
You can put this solution on YOUR website!t varies inversely as r is written as t = k/r where k is the constant of proportionality.
We first need to find k plugging 5 for t and 55 for r.
5 = k/55
5*55 = k
275 = k
We now need to find t when k = 275 and r = 40.
t = k/r
t = 275/40
t = 6.875 hours
Question 241024: I need help on factor by grouping y^2-6y+4y-24
Answer by checkley77(7049) (Show Source):
Question 241005: -16+z=-8
Answer by dspence(2) (Show Source):
Question 241083: I have to combine like terms or equation. I want to know did I do this promblem right 4+4+9x+10x=8+19x
Answer by nyc_function(260) (Show Source):
You can put this solution on YOUR website!Simply combine constants with constants and terms with terms.
4+4+9x+10x=8+19x
8 + 19x = 8 + 19x
Do you see what's going on here?
There is no solution to this linear equation.
When we combine like terms at this point, we get 0 = 0, which means NO SOLUTION.
Question 241044: Simplify if possible
(-2)/(y^2-9)+4y/((y-3)^2)+6/(3-y)
Answer by jsmallt9(590) (Show Source):
You can put this solution on YOUR website!
In order to add these (or any) fractions you must have common denominators. If the denominators are not the same you must make them the same before you add. It is much easier, especially with fractions of polynomials like these, to use the Lowest Commmon Denominator (LCD). To find the LCD you first factor the denominators. So we start by factoring each denominator.
The first denominator is a difference of squares and will factor according to the pattern . The second denominator is already factored and there is not much factoring that can be done with the third denominator. So let's factor the first denominator and see what we have:
At this point it looks like we have 3 different factors among the denominators: (y+3), (y-3) and (3-y). But if we can reduce the number of factors it will make things easier. And we can reduce the number of factors if we recognize that (y-3) and (3-y) are negatives of each other. So if we multiply the numerator and denominator of the third fraction by -1 then we will have just two factors among the denominators:
Now, with just the two factors, the LCD is the product of these factors (using the higher exponent for each common factor). So the LCD is:
Next we multiply the numerator and denominator of each fraction by whatever factors of the LCD its denominator is missing, if any:
We will multiply the numerators but we will leave the denominators factored for now:
With the denominators the same we can now add:
And finally, as usual with answers that are fractions, we reduce the fraction if we can. And to reduce any fraction we have to find common factors. So we need the numerator and denominator factored. The denominator is already factored. (This is why we did not multiply it out earlier!) So we just have to factor the numerator:
The numerator does not factor any more than this. And we can see that there are no common factors to cancel. So we cannot reduce this fraction. So the answer is either the fraction above or the multiplied out version of the fraction above (depending on which form is preferred):
Question 240938: could someone help me solve for x in this expression?
x+1/x+5=x+2/x+4 I am still struggling.
Answer by ankor@dixie-net.com(6693) (Show Source):
You can put this solution on YOUR website!solve for x in this expression?
x+1/x+5=x+2/x+4
:
Assume the problem is:
 = 
Cross multiply and you have:
(x+5)*(x+2) = (x+1)*(x+4)
FOIL
x^2 + 7x + 10 = x^2 + 5x + 4
:
Group x's on the left, numbers on the right
x^2 - x^2 + 7x - 5x = 4 - 10
2x = -6
x = 
x = -3
;
Leave it to you to substitute -3 for x in the original problem, and check for equality
Question 240970: what is 9x^4-4y^2 completely factored?
Found 2 solutions by Earlsdon, stanbon:
Answer by Earlsdon(4900) (Show Source):
Answer by stanbon(26268) (Show Source):
Question 240870: (x+1)(x-1)
Answer by checkley77(7049) (Show Source):
Question 240871: (x+1)(x-1)
Answer by checkley77(7049) (Show Source):
Question 240878: (x+1)(x-1)
Answer by checkley77(7049) (Show Source):
Question 240914: Factor.
x^2 –3xy -18y^2
Answer by edjones(3294)  (Show Source):
Question 240919: Multiply and simply:
2x(x-2)(x+2)
So far I did 2x^3 but i need help from that point on..please and thanks!
Answer by Earlsdon(4900) (Show Source):
Question 240921: Factor:
3x^4-81
Answer by Earlsdon(4900) (Show Source):
Question 240898: need to solve this problem but have no idea where to start
12(a+b)^2 + 29(a+b) + 15
Answer by stanbon(26268) (Show Source):
You can put this solution on YOUR website!need to solve this problem but have no idea where to start
12(a+b)^2 + 29(a+b) + 15
--------------------------------
This is a quadratic equation with (a+b) being the variable.
Let w = a+b
----
Rewrite the equation using "w"
12w^2 + 29w + 15
Factor:
(4w+3)(3w+5)
-----------------------
Rewrite the factors using a+b:
(4(a+b)+3)(3(a+b)+5)
================================
Cheers,
Stan H.
Question 240909: How do you solve
(px+q)(2x+5)=6xx+11x+r
Answer by solver91311(5072) (Show Source):
Question 240891: I cannot seem to figure out how this expression was simplified. Could someone show me how it was done?
x^2+4x+3=x^2+6x+8 simplified = -2x=5 which the solution is -5/2 I need to know how this was done. Thanks. I have a hard time simplifying.
Answer by stanbon(26268) (Show Source):
You can put this solution on YOUR website!I cannot seem to figure out how this expression was simplified. Could someone show me how it was done?
x^2+4x+3=x^2+6x+8 simplified = -2x=5 which the solution is -5/2 I need to know how this was done
-------------------------
x^2+4x+3=x^2+6x+8
---
Subtract x^2 from both sides:
4x+3 = 6x+8
Subtract 4x from both sides:
3 = 2x + 8
Subtract 8 from both sides:
2x = -5
Divide both sides by 2 to get:
x = -5/2
===================================
Cheers,
Stan H.
Question 240841: Solve by factoring: 5x^2=10x
Answer by rapaljer(3620) (Show Source):
You can put this solution on YOUR website!First, you must set this equation equal to zero!
5x^2-10x =0
Now factor the left side. There is a common factor of 5x:
5x(x-2)=0
There are two solutions.
5x= 0
x=0
OR x-2=0
x=2
I have a LOT of resources on my own website on the topics of FACTORING and SOLVING QUADRATIC EQUATIONS. To find my website, do a "BING" or a "GOOGLE" search for my last name "Rapalje". Near the top of the search list, you should see "Rapalje Homepage." Click on this, and look near the top of my homepage for the link "Basic, Intermediate and College Algebra: One Step at a Time." Choose "Basic Algebra", and look in "Chapter 2 for the appropriate sections. This is my own explanation especially written for students who have trouble understanding math. I wrote this to students, NOT mathematicians, and I think you will find it easier to understand than your own traditional textbooks!! In addition to this page, the entire website is supported by my "MATH IN LIVING COLOR" pages, where the hardest problems are solved IN COLOR.
If you like my website, please recommend it to family and friends who have trouble understanding math!! It's ALL FREE!!!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Question 240663: 9/x-4 = 9x+36/?
How will I solve if neither of the numerator or the denominator is missing?
Answer by vleith(1977) (Show Source):
You can put this solution on YOUR website!Let the ? be represented by z. Now solve for z
 Use distribution on the left side numerator
 divide both sides by 9
 multiply both sides by z
 isolate z
 simplify
Question 240598: Grouping:
x^3+x^2+x+1
Answer by rapaljer(3620) (Show Source):
You can put this solution on YOUR website!Group the first two and the last two together. From the first two take out a common factor of x^2. From the last two, take out a common factor (since there is actually NOT one!) of 1.
x^3+x^2 + x +1
x^2(x+1)+1(x+1)
Notice that you have a common factor of (x+1). Take out this common factor:
(x+1)(x^2 + 1)
There are a several links on my own website that explain FACTORING in detail. To find my website, do a "Bing" or "Google" search for my last name "Rapalje". Look for "Rapalje Homepage" near the top of the search list. Near the top of my Homepage, look for "Basic, Intermediate and College Algebra: One Step at a Time." In "Basic Algebra" look in Chapter 2 for "Section 2.07 Factoring by Grouping." My non-traditional explanations are probably easier to understand than your own textbook.
In addition, I have a FREE video that might help. From my homepage, look for the link "Rapalje Vidoes in Living Color". Choose "Basic Algebra" and look for "Factoring". Try it and see what you think--it's all FREE!!
If you like my website, please recommend it to friends!!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Question 240609: Find the Polynoial of lowest degree that has the zeros, 4,-4, 1, -1.
Answer by rapaljer(3620) (Show Source):
You can put this solution on YOUR website!P(X)= (x-4)(x+4)(x-1)(x+1)
P(x) = (x^2-16)(x^-1)
P(x)=x^4 -17x^2+16
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Question 240640: Please help me figure this problem. I am new to Algebra so I have no clue. The problem is: Find the equation for the line with the given properties. Perpendicular to the line -5x-y=7; containing the point (0, -7/5)
Thank-you very much
Answer by rapaljer(3620) (Show Source):
You can put this solution on YOUR website!To find the slope of the given line, you must solve for y.
-5x-y=7
-y=5x+7
y=-5x-7
The slope of the line is the coefficient of x, which in this case is m=-5.
The slope of a line PERPENDICULAR to this line is the NEGATIVE RECIPROCAL of this slope, which is 1/5.
The given point just happens to be the y-intercept (0,-7/5)
The equation of a line with slope m that passes through the y-intercept (0,b) is y=mx+b.
The equation of a line with slope 1/5 that passes through the point (0,-7/5) is 
There are a couple of links on my own website that explain this topic in detail. To find my website, do a "Bing" or "Google" search for my last name "Rapalje". Look for "Rapalje Homepage" near the top of the search list. Near the top of my Homepage, look for "Basic, Intermediate and College Algebra: One Step at a Time." In "Basic Algebra" look in Chapter 4 for "Section 4.06 The Equation of a Line." My non-traditional explanations are probably easier to understand than your own textbook. Try it and see what you think.
If you like my website, please recommend it to friends!!
Dr. Robert J. Rapalje, Retired
Seminole State College of Florida
Altamonte Springs Campus
Question 240597: Quadratic Trinomials : Factor each polynomial completely.
x^2-5x+4
Answer by stanbon(26268) (Show Source):
Question 240560: Factor this equation:
2pq-4p^2+2pr
I am trying to help my son and am totally lost.
Answer by scott8148(3382)  (Show Source):
Question 240538: Please help me out with this equation:
7/8 - 2/11 = x/44
I multiplied the two sides by the LCD, and ended up with a fraction that could not be reduced, but the question was asking for an answer in reduced form.
Please help me! It would be greatly appreciated!
Answer by scott8148(3382) (Show Source):
Question 240497: a natural number greater than one that is divisible only by one and itself is said to be this.
Answer by jsmallt9(590) (Show Source):
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Older solutions: 1..45, 46..90, 91..135, 136..180, 181..225, 226..270, 271..315, 316..360, 361..405, 406..450, 451..495, 496..540, 541..585, 586..630, 631..675, 676..720, 721..765, 766..810, 811..855, 856..900, 901..945, 946..990, 991..1035, 1036..1080, 1081..1125, 1126..1170, 1171..1215, 1216..1260, 1261..1305, 1306..1350, 1351..1395, 1396..1440, 1441..1485, 1486..1530, 1531..1575, 1576..1620, 1621..1665, 1666..1710, 1711..1755, 1756..1800, 1801..1845, 1846..1890, 1891..1935, 1936..1980, 1981..2025, 2026..2070, 2071..2115, 2116..2160, 2161..2205, 2206..2250, 2251..2295, 2296..2340, 2341..2385, 2386..2430, 2431..2475, 2476..2520, 2521..2565, 2566..2610, 2611..2655, 2656..2700, 2701..2745, 2746..2790, 2791..2835, 2836..2880, 2881..2925, 2926..2970, 2971..3015, 3016..3060, 3061..3105, 3106..3150, 3151..3195, 3196..3240, 3241..3285, 3286..3330, 3331..3375, 3376..3420, 3421..3465, 3466..3510, 3511..3555, 3556..3600, 3601..3645, 3646..3690, 3691..3735, 3736..3780, 3781..3825, 3826..3870, 3871..3915, 3916..3960, 3961..4005, 4006..4050, 4051..4095, 4096..4140, 4141..4185, 4186..4230, 4231..4275, 4276..4320, 4321..4365, 4366..4410, 4411..4455, 4456..4500, 4501..4545, 4546..4590, 4591..4635, 4636..4680, 4681..4725, 4726..4770, 4771..4815, 4816..4860, 4861..4905, 4906..4950, 4951..4995, 4996..5040, 5041..5085, 5086..5130, 5131..5175, 5176..5220, 5221..5265, 5266..5310, 5311..5355, 5356..5400, 5401..5445, 5446..5490, 5491..5535, 5536..5580, 5581..5625, 5626..5670, 5671..5715, 5716..5760, 5761..5805, 5806..5850, 5851..5895, 5896..5940, 5941..5985, 5986..6030, 6031..6075, 6076..6120, 6121..6165, 6166..6210, 6211..6255, 6256..6300, 6301..6345, 6346..6390, 6391..6435, 6436..6480, 6481..6525, 6526..6570, 6571..6615, 6616..6660, 6661..6705, 6706..6750, 6751..6795, 6796..6840, 6841..6885, 6886..6930, 6931..6975, 6976..7020, 7021..7065, 7066..7110, 7111..7155, 7156..7200, 7201..7245, 7246..7290, 7291..7335, 7336..7380, 7381..7425, 7426..7470, 7471..7515, 7516..7560, 7561..7605, 7606..7650, 7651..7695, 7696..7740, 7741..7785, 7786..7830, 7831..7875, 7876..7920, 7921..7965, 7966..8010, 8011..8055, 8056..8100, 8101..8145, 8146..8190, 8191..8235, 8236..8280, 8281..8325, 8326..8370, 8371..8415, 8416..8460, 8461..8505, 8506..8550, 8551..8595, 8596..8640, 8641..8685, 8686..8730, 8731..8775, 8776..8820, 8821..8865, 8866..8910, 8911..8955, 8956..9000, 9001..9045, 9046..9090, 9091..9135, 9136..9180, 9181..9225, 9226..9270, 9271..9315, 9316..9360, 9361..9405, 9406..9450, 9451..9495, 9496..9540, 9541..9585, 9586..9630, 9631..9675, 9676..9720, 9721..9765, 9766..9810, 9811..9855, 9856..9900, 9901..9945, 9946..9990, 9991..10035, 10036..10080, 10081..10125, 10126..10170, 10171..10215, 10216..10260, 10261..10305, 10306..10350, 10351..10395, 10396..10440, 10441..10485, 10486..10530, 10531..10575, 10576..10620, 10621..10665, 10666..10710, 10711..10755, 10756..10800, 10801..10845, 10846..10890, 10891..10935, 10936..10980, 10981..11025, 11026..11070, 11071..11115, 11116..11160, 11161..11205, 11206..11250, 11251..11295, 11296..11340, 11341..11385, 11386..11430, 11431..11475, 11476..11520, 11521..11565, 11566..11610, 11611..11655, 11656..11700, 11701..11745, 11746..11790, 11791..11835, 11836..11880, 11881..11925, 11926..11970, 11971..12015, 12016..12060, 12061..12105, 12106..12150, 12151..12195, 12196..12240, 12241..12285, 12286..12330, 12331..12375, 12376..12420, 12421..12465, 12466..12510, 12511..12555, 12556..12600, 12601..12645, 12646..12690, 12691..12735, 12736..12780, 12781..12825, 12826..12870, 12871..12915, 12916..12960, 12961..13005, 13006..13050, 13051..13095, 13096..13140, 13141..13185, 13186..13230, 13231..13275, 13276..13320, 13321..13365, 13366..13410, 13411..13455, 13456..13500, 13501..13545, 13546..13590, 13591..13635, 13636..13680, 13681..13725, 13726..13770, 13771..13815, 13816..13860, 13861..13905, 13906..13950, 13951..13995, 13996..14040, 14041..14085, 14086..14130, 14131..14175, 14176..14220, 14221..14265, 14266..14310, 14311..14355, 14356..14400, 14401..14445, 14446..14490, 14491..14535, 14536..14580, 14581..14625, 14626..14670, 14671..14715, 14716..14760, 14761..14805, 14806..14850
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