# SOLUTION: Please help me, I can not get this to factor- 7x^2+34x-5

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 93699: Please help me, I can not get this to factor- 7x^2+34x-5Found 4 solutions by stanbon, praseenakos@yahoo.com, ankor@dixie-net.com, jayanthihemkos@yahoo.com:Answer by stanbon(60772)   (Show Source): You can put this solution on YOUR website!factor- 7x^2+34x-5 = (7x-1)(x+5) ============== Cheers, Stan H. Answer by praseenakos@yahoo.com(507)   (Show Source): You can put this solution on YOUR website!Question: Please help me, I can not get this to factor- 7x^2+34x-5 Answer: Here you can use the method of splitting middle term.. For that you have to find out two numbers so that their sum is +34(that is coefficient of x ) and whose product is -35( that is 7 * -5) Such two numbers are +35 and -1 Now split the middle term using these two numbers. ==> Now group the terms as follows... ==> Now take out the common terms form each group.... ==> Now (1x + 5) is common in both groups, so take it outside. ===> (1x + 5 ) ( 7x + 5 ) = 0, So the factors of the given equation is ======================================================================== If you want to solve this equation..... (1x + 5 ) ( 7x + 5 ) = 0 ==> either (1x + 5 ) = 0 or ( 7x + 5 ) = 0 (1x + 5 )= 0 ==> and ( 7x + 5 ) = 0 ==> 7x = -5 ==> Hope you found the explanation useful. Regards. Praseena Answer by ankor@dixie-net.com(16524)   (Show Source): You can put this solution on YOUR website!factor- 7x^2 + 34x - 5 : You can see that 7 only has 1 & 7 as factors Also 5 has only 5 and 1 as factors : You know it will be this because the middle term is 34 (7*5): (7x__ 1)(x___5) : Now just find the signs that will make this thing work (7x - 1)(x + 5) : Check it by FOILing these factors; 7x^2 + 35x - 1x - 5 = 7x^2 + 34x -5 : Did this help? Answer by jayanthihemkos@yahoo.com(87)   (Show Source): You can put this solution on YOUR website!7x^2+34x-5 Here we apply quadratic formula x= -b+or- sqrt of b^2 -4ac/2a here a = 7 , b= 34 , c= -5 ==> -34 +/- sqrt of (34)^2-( 4*7*-5)/2*7 ==> -34 +/- sqrt of 1156+140/14 ==> -34+/- sqrt of 1296/14 ==> -34 +/- 36/14 ==> 2( -17 +/- 18)/2*7 ( 2 is taken as common factor) ==>-17 +/- 18 /7 ( 2 in the numerator and denominator gets cancelled) x = -17 + 18/ 7 and -17 -18/7 x = 1/7 and x = -35/7 = -5 Hence the solution for x= 1/7 and -5