# SOLUTION: Find the polynominal f(x) of degree three that has zeros at 1,2 and 4 such that f(0)=-16.

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 66312: Find the polynominal f(x) of degree three that has zeros at 1,2 and 4 such that f(0)=-16.Answer by ankor@dixie-net.com(16527)   (Show Source): You can put this solution on YOUR website!Find the polynominal f(x) of degree three that has zeros at 1,2 and 4 such that f(0)=-16. : The 3 factors will be (x-1)(x-2)(x-4), : FOIL (x-1)(x-2) = x^2 -3x + 2, : multiply by (x-4) and you get: x^3 - 7x^2 + 14x - 8; : But wait, it says f(0) = -16, so last term has to be -16: Multiply the equation by 2 (,it will not effect the zeros) : 2x^3 - 14x^2 + 28x - 16 is the equation that satisfies all these requirements