SOLUTION: I'm stuck on how to solve this one (2X^3-7X^2-4)/(2X-3) I set it up in long division and so far i got (2X-3/2X^3-7X^2-4) I put x^2 above 7X^2 and i multiplied it makin

Algebra ->  -> SOLUTION: I'm stuck on how to solve this one (2X^3-7X^2-4)/(2X-3) I set it up in long division and so far i got (2X-3/2X^3-7X^2-4) I put x^2 above 7X^2 and i multiplied it makin      Log On

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 Question 58298: I'm stuck on how to solve this one (2X^3-7X^2-4)/(2X-3) I set it up in long division and so far i got (2X-3/2X^3-7X^2-4) I put x^2 above 7X^2 and i multiplied it making it look like this now 2x^3-7x^2 minus 2x^3-7x^2=4X^2-4. i dont know what to do anymore. Answer by ankor@dixie-net.com(16527)   (Show Source): You can put this solution on YOUR website!(2X^3-7X^2-4)/(2X-3) Your Answer: (2X^3-7X^2-4)/(2X-3) : Using long division, note that each degree of the equation has to be placed so 0x is inserted: [Used ......... to keep things lined up] ...............................x^2 - 2x - 3 ............--------------------------- (2x-3) | 2x^3 - 7x^2 - 0x - 4 ................2x^3 - 3x^2 ................------------- ..............................-4x^2 - 0x ..............................-4x^2 + 6x ...............................----------- ...........................................-6x - 4 ...........................................-6x + 9 ...........................................-------- ..................................................-13 : The solution: x^2 - 2x - 3; remainder -13/(2x-3)