Question 427670: I need help could someone please explain this to me?
the equation of the line that is perpendicular to the graph of y=1/3x-4; passing through (0,-1) Answer by ewatrrr(11176) (Show Source):
Using the standard slope-intercept form for an equation of a line y = mx + b
where m is the slope and b the y-intercept.
y=1/3x-4 |Slope m = (1/3) AND the slope of a line perpendicular to it is -3/1
Perpendicular Lines have slopes that are negative reciproclas of one another.
y = -3x + b |using Pt(0,1) to solve for b
1 = -3*0 + b
1 = b EQ of this line is y = -3x+1