# SOLUTION: I need help could someone please explain this to me? the equation of the line that is perpendicular to the graph of y=1/3x-4; passing through (0,-1)

Algebra ->  -> SOLUTION: I need help could someone please explain this to me? the equation of the line that is perpendicular to the graph of y=1/3x-4; passing through (0,-1)      Log On

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 Question 427670: I need help could someone please explain this to me? the equation of the line that is perpendicular to the graph of y=1/3x-4; passing through (0,-1)Answer by ewatrrr(11176)   (Show Source): You can put this solution on YOUR website! ``` Hi Using the standard slope-intercept form for an equation of a line y = mx + b where m is the slope and b the y-intercept. y=1/3x-4 |Slope m = (1/3) AND the slope of a line perpendicular to it is -3/1 Perpendicular Lines have slopes that are negative reciproclas of one another. New Line: y = -3x + b |using Pt(0,1) to solve for b 1 = -3*0 + b 1 = b EQ of this line is y = -3x+1 ```