# SOLUTION: A jar of dimes and quarters contains \$15.25. There are 103 coins in all. How many quarters in the jar? thanx

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 40015: A jar of dimes and quarters contains \$15.25. There are 103 coins in all. How many quarters in the jar? thanxAnswer by AnlytcPhil(1321)   (Show Source): You can put this solution on YOUR website!```A jar of dimes and quarters contains \$15.25. There are 103 coins in all. How many quarters in the jar? thanx Let D = the number of dimes and Q be the number of quarters >>...There are 103 coins in all...<< Therefore D + Q = 103 >>...A jar of dimes and quarters contains \$15.25...<< The money which the D dimes is worth is \$.10 times D or .10D The money which the Q quarters is worth is \$.25 times Q or .25D So .10D + .25D = 15.25 We have this system: D + Q = 103 .10D + .25D = 15.25 Can you solve that system? If not post again. Answer 70 dimes and 33 quarters Edwin McCravy AnlytcPhil@aol.com```