Question 344861: Question: 4- a-b/a+4 = a^2-6/a+4
Here's what I've got so far.
LCM is a+4
(a+4)(4- a-b/a+4) = (a=4)(a^2-6/a+4)
4(a=4) - a-b/a+4 (a+4) = (a+4)a^2+6/a+4=
4a +4 * 4 - (a-b) = a^2 -6
Then I'm supposed to simplify,
I've got the
3a +16???? What do I do with the b?
After simplifying, I'm supposed to write the result as a quadratic equation by 3a and 16 from sides and simplifying, then solve the quadratic equation.
Please help, I'm stumped. I also have not figured out how to post a thank you for help on this site. Answer by stanbon(60771) (Show Source):
You can put this solution on YOUR website! 4- (a-6)/(a+4) = (a^2-6)/(a+4)
Multiply thru by (a+4) to get:
4(a+4) - (a-6) = a^2-6
4a+16 -a+6 = a^2-6
3a+16+6 = a^2-6
a^2-3a-22 = 6
a^2-3a-28 = 0
(a-7)(a+4) = 0
a = 7 or a = -4
Only a=7 is a solution.