# SOLUTION: HEY, MY NAME IS KWAISHAWN AND I'M TAKING ALGEBRA 2. TODAY, I HAVE HOMEWORK AND I RAN INTO A PROBLEM. NOW I KINDA UNDERSTAND IT BUT NOT AS GOOD AS I WANT TO BE. (YOU KNOW WHAT I MEA

Algebra ->  -> SOLUTION: HEY, MY NAME IS KWAISHAWN AND I'M TAKING ALGEBRA 2. TODAY, I HAVE HOMEWORK AND I RAN INTO A PROBLEM. NOW I KINDA UNDERSTAND IT BUT NOT AS GOOD AS I WANT TO BE. (YOU KNOW WHAT I MEA      Log On

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 336887: HEY, MY NAME IS KWAISHAWN AND I'M TAKING ALGEBRA 2. TODAY, I HAVE HOMEWORK AND I RAN INTO A PROBLEM. NOW I KINDA UNDERSTAND IT BUT NOT AS GOOD AS I WANT TO BE. (YOU KNOW WHAT I MEAN) TOMORROW, WE ARE GOING TO HAVE A QUIZ AND I NEED TO BE ON MY A-GAME. SO HERE THE PROBLEM AND CAN YOU PLEASE EXPLAIN IT SO I CAN GET A BETTER UNDERSTANDING. THANKS! DIRECTIONS: FACTOR COMPLETELY. 8X SQUARED PLUS 8XY PLUS 8XZ PLUS 3X PLUS 3Y PLUS 3Z I KNOW YOU WON'T BE ABLE TO SHOW ME TONIGHT, BUT I WILL APPRECIATE IF YOU GIVE IT TO ME AS SOON AS POSSIBLE BECAUSE TEST IS ON FRIDAY AND GIRL GOT TO ACE IT. Answer by ankor@dixie-net.com(16525)   (Show Source): You can put this solution on YOUR website!8X SQUARED PLUS 8XY PLUS 8XZ PLUS 3X PLUS 3Y PLUS 3Z : 8x^2 + 8xy + 8xz + 3x + 3y + 3z : We have two groups of common values 8x and 3 (8x^2 + 8xy + 8xz) + (3x + 3y + 3z) : Factor out 8x and 3 8x(x + y + z) + 3(x + y + z) ; Now we can factor out (x+y+z) from 8x and 3 and we have (x + y + z)(8x + 3)