# SOLUTION: The area of rectangle ABCD is {{{ 20 cm^2 }}}. If the width is 7 cm more than 3 times the length, what are the dimensions of the triangle? Use a polynomial equation to solve the

Algebra ->  -> SOLUTION: The area of rectangle ABCD is {{{ 20 cm^2 }}}. If the width is 7 cm more than 3 times the length, what are the dimensions of the triangle? Use a polynomial equation to solve the      Log On

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 Click here to see ALL problems on Polynomials-and-rational-expressions Question 301468: The area of rectangle ABCD is . If the width is 7 cm more than 3 times the length, what are the dimensions of the triangle? Use a polynomial equation to solve the problem It would also be helpful if you included the initial equation so I could understand it better.Answer by checkley77(12569)   (Show Source): You can put this solution on YOUR website!AREA=L*W W=3L+7 20=L(3L+7) 20=3L^2+7L 3L^2+7L-20)=0 (3L-5)(X+4)=0 3L-5=0 3L=5 L=5/3 ANS. W=3*5/3+7=5+7=12 ANS. PROOF: 20=5/3*12 20=5*4 20=20