SOLUTION: how many sides does a regular polygon have if one of the exterior angles=9. and how many sides does a regular polygon have if one of the exterior angles=11.25?

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Question 960194: how many sides does a regular polygon have if one of the exterior angles=9. and how many sides does a regular polygon have if one of the exterior angles=11.25?
Answer by Edwin McCravy(20066)   (Show Source): You can put this solution on YOUR website!
how many sides does a regular polygon have if one of the exterior angles=9°?
The sum of the exterior angles of a polygon is 360° and since there are n
exterior angles all with the same measure,

360°/n = 9°

Multiply both sides by n

360° = 5°n

Divide both sides by 5°

72 = n

That's the answer.  

[Incidentally, a 72-sided regular polygon would be hard to tell
from a circle, unless it were very large.]


and
how many sides does a regular polygon have if one of the exterior angles=11.25°?
360°/n = 11.25°

Multiply both sides by n

360° = 11.25°n

Divide both sides by 11.25°

32 = n

Answer: 32 sides. Here's how a 32-sided regular polygon looks.
The green lines are drawn from the center to the vertices, and
would all be radii of a circumscribing circle:



Edwin


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