SOLUTION: This regular pentagon whose sides all measure 9 feet is made up of five triangles each having a height of 6.2 feet. What is the area of this pentagon?

Algebra.Com
Question 944055: This regular pentagon whose sides all measure 9 feet is made up of five triangles each having a height of 6.2 feet. What is the area of this pentagon?
Answer by macston(5194)   (Show Source): You can put this solution on YOUR website!
For each triangle, area=1/2(b)(h), so for the entire pentagon:
b=base or side=9 feet, h=height=6.2 feet(given)
Total area=(5)(1/2)(9 feet)(6.2 feet)=139.5 sq ft ANSWER
Total Area of the pentagon is 139.5 sq ft

RELATED QUESTIONS

A regular pentagon can be dissected into 5 isosceles triangles whose vertex angle is at... (answered by mangopeeler07)
1. An exterior angle of a regular polygon measures 30 degrees. What is the measure of an... (answered by Fombitz)
a pentagon is a five-sided figure.in the pentagon,all five sides are equal and are... (answered by checkley71)
what is the area of a regular pentagon with a side length of 7 feet and a length from... (answered by KMST)
My question: Classify the triangle whose sides each measure 6 feet. also.. What would... (answered by MathLover1)
what is the measure of the area of a parallelogram whose base is 5 1/2 feet and whose... (answered by Alan3354)
What is the measure of each interior angle of a regular... (answered by jb007mi6)
What is the measure of each interior angle for a regular... (answered by solver91311)
What is the name of a figure that has 2 sides that measure 25 feet each and 2 sides that... (answered by solver91311)