SOLUTION: Question - the angle sum of an irregular polygon is 1260 degrees.how many sides has it got My comment - from my knowledge you cant find the number of sides in and irregular poly

Question 837265: Question - the angle sum of an irregular polygon is 1260 degrees.how many sides has it got
My comment - from my knowledge you cant find the number of sides in and irregular polygon because all the angles have diffrent measurements.Instead of taking nothing to class i thought maybe theres an error in the textbook so i did the question but with a regular polygon and i did this...... 1260/180=7 and 7+2=9 this is the reverse of the formula to find the angle sum {(n-2)*180} please can you tell me if its posible to do this with an irregular polygon and ifso can you show me the full workout with an explanation. THANK YOU
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
same number of sides and angles in regular and irregular.
same formulas you can't know the sizes of each angle and side but you can know how many there are are.

RELATED QUESTIONS
The angle of an irregular polygon is 1260 degrees. how many sides has... (answered by stanbon)

The sum of the interior angle measures of a convex polygon is 1260 degrees . How many... (answered by Alan3354)

a regular polygon has n sides. The sum of the interior angles of the polygon is 1260... (answered by Earlsdon)

A polygon has an interior angle sum of 3060. How many sides must the polygon... (answered by greenestamps)

a regular polygon has an interiaor angle of 170 degrees. how many sides does it have?... (answered by HyperBrain)

how many sides does a polygon have if it has an interior angle of 145... (answered by stanbon)

if a polygon has an exterior angle of 18 degrees, how many sides does it... (answered by Alan3354)

A polygon has an exterior angle of 5 degrees how many sides does it have (answered by Alan3354)

The sum of the interior angle measures of a convex polygon is 1980 degrees . How many... (answered by Alan3354,MathLover1)