SOLUTION: a and b are regular polygons and a has 2 more sides than B. The measure of each interior angle of A is 6 greater than the measure of each interior angle of B. How many sides does A

Question 828524: a and b are regular polygons and a has 2 more sides than B. The measure of each interior angle of A is 6 greater than the measure of each interior angle of B. How many sides does A have?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
a and b are regular polygons and a has 2 more sides than B. The measure of each interior angle of A is 6 greater than the measure of each interior angle of B. How many sides does A have?
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The Exterior angles differ by 6.
a = b + 2
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360/b = 360/(b+2) + 6
360/b = (360 + 6b + 12)/(b+2)
360*(b+2) = b*(6b + 372)
360b + 720 = 6b^2 + 372b
b^2 + 2b - 120 = 0
b = 10
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a = 12

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