SOLUTION: how many sides has a polygon if the sum of its interior angles is twice that of an octagon
Algebra.Com
Question 625849: how many sides has a polygon if the sum of its interior angles is twice that of an octagon
Answer by opeodu(24) (Show Source): You can put this solution on YOUR website!
(n-2)*180¤=2*(8-2)*180¤ n-2=2*6 n-2=12 n=12+2 n=14
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