The sum of the four internal angles of a quadrilateral is 360°. Since ∠A is 60°, that leaves 300° for the sum of angles ∠A, ∠BCD, and ∠D. Therefore they are 100° each since they are equal. ∠A and ∠CED are equal since they are corresponding angles when transversal AD cuts parallel lines AB and CE, and so ∠CED = 60°. The three interior angles of ᐃECD must have sum 180°, and since ∠CED = 60° and ∠D = 100°, they sum to 160°, leaving ∠ECD = 20° Edwin