SOLUTION: how many sides does a polygon have if the sum of its angle measures is 2700
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Question 553148: how many sides does a polygon have if the sum of its angle measures is 2700
Found 2 solutions by jim_thompson5910, solver91311:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
S = 180(n-2)
2700 = 180(n-2)
2700/180 = n-2
15 = n-2
15+2 = n
17 = n
n = 17
So there are 17 sides.
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Jim
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The sum of the interior angle measures of an 
-sided polygon is given by:
)
So solve:
\ =\ 2700)
for
John
My calculator said it, I believe it, that settles it
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