SOLUTION: If the sum of the measures of the interior angles of a polygon is twice the sum of its exterior angles how many sides does it have
Algebra.Com
Question 553084: If the sum of the measures of the interior angles of a polygon is twice the sum of its exterior angles how many sides does it have
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
180(n-2) = 2*360
180(n-2) = 720
n - 2 = 720/180
n - 2 = 4
n = 4+2
n = 6
So there are 6 sides and this figure is a hexagon.
RELATED QUESTIONS
IF the sum of the measures of the interior angles of a polygon is twice the sum of its... (answered by Gogonati)
Find the number of sides of a polygon if the sum of the measures of its interior angles... (answered by Alan3354)
How many sides has a polygon in which the sum of the interior angles of the polygon is... (answered by Alan3354)
The sum of the interior angles of a polygon is twice the sum of its exterior angles. How... (answered by Theo,ikleyn)
How many sides does a polygon have if the sum of its interior angles is 7 times the sum... (answered by Theo,greenestamps)
How many sides does a polygon have if the sum of its interior angles is seven times the... (answered by Theo,greenestamps)
How many sides does a polygon have if the sum of the measures of its interior angles is 6 (answered by psychopsibilin)
The sum of interior angles of a convex polygon is ten times the sum of its exterior... (answered by reviewermath)
the sum of the measures of the interior angles of a polygon is the same as the sum of the (answered by Don2xmalabag)