SOLUTION: a) graph the lines x=0, x=6, y=0 and y=x+4 b) what type of quadrilateral do the lines form? c) find the area of the quadrilateral

Question 484500: a) graph the lines x=0, x=6, y=0 and y=x+4
b) what type of quadrilateral do the lines form?
c) find the area of the quadrilateral
Answer by tinbar(133) (Show Source): You can put this solution on YOUR website!
I'm not sure how to explain the graph to you, but here goes: x=0 is a vertical line that goes through the point x=0(Same as the y-axis). x=6 is similar, a vertical line, but this one goes through the point x = 6. Next, y=0, is a horizontal line that goes through the point y=0(Same as the x-axis). Finally y=x+4, is a diagonal line (45 degrees) that goes through the point (0,4) and (6,10). So if you can plot these two points and draw a line through them, that line would be y=x+4.
Ultimately, in the graph, the lower left corner of the shape is at (0,0). The lower right corner is at (6,0). The upper left corner is at (0,4). The upper right corner is at (6,10). Once you have these points plotted, join them to make your shape, you should get a trapezoid.
Now to find the area: there are many ways to do this. I am going to split the shape up into a rectangle and a triangle, and take their areas respectively and add to get the total area.
The square is described by the points: (0,0),(0,4),(6,0), and (6,4). One side is 6 units, the other side is 4 units, giving us an area of 6*4 = 24 units.
The triangle is described by the points: (0,4),(6,4), and (6,10). The base is 6 units, the height is also 6 units, which gives us an area of 6*6/2 = 36/2 = 18.
We add for the total area to get 24+18 = 42 units.
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