prob best to draw the triagle to visualize an equalateral triangle meaning all sides the same the radius is 3 and also it disects the base side at a 90 degree angle and the base is seperated in 2 equal segments. so if x= the hypotenuse of the right triagle which is the same as the length of one side of the equalateral triangle then the base of the right triangle has to be now i would do the therom where a=6 b=(1/2)x and c=x
the hieght of the right triangle is 2*(radius) so 2*3=6
divide by 3
sqrt each side
so b=base h=hieght a=area