# SOLUTION: A piece of wire is shaped to enclose an equilateral triangle whose area is (16 (sqrt 3) ) cm^2. It is then reshaped to enclose a rectangle whose length is 9 cm. Find the area of th

Algebra ->  Algebra  -> Polygons -> SOLUTION: A piece of wire is shaped to enclose an equilateral triangle whose area is (16 (sqrt 3) ) cm^2. It is then reshaped to enclose a rectangle whose length is 9 cm. Find the area of th      Log On

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 Question 234893: A piece of wire is shaped to enclose an equilateral triangle whose area is (16 (sqrt 3) ) cm^2. It is then reshaped to enclose a rectangle whose length is 9 cm. Find the area of the rectangle. >>Please show your solution. ThanksAnswer by solver91311(16897)   (Show Source): You can put this solution on YOUR website! The area of an equilateral triangle given the measure of one side, , is: . Therefore: Therefore the perimeter of the triangle, and the length of the wire is 24. The perimeter of a rectangle is: So: So the width is If the length is 9 and the width is 3, the area must be 27. John