SOLUTION: if the exterior angles of a convex polygon are x/13, 2x-1, 2x/6,2x+12,2x-17,3x-4,3x-10 and 4x calculate the smallest of eight angles.
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Question 191062: if the exterior angles of a convex polygon are x/13, 2x-1, 2x/6,2x+12,2x-17,3x-4,3x-10 and 4x calculate the smallest of eight angles.
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The sum of the exterior angles of a polygon, regular or otherwise, and regardless of the number of sides, is 180°.
So solve:  + (2x-1) + \left({2x \over 6}\right) + (2x+12) + (2x-17) + (3x-4) + (3x-10) + (4x) = 180)
for x.
Hint: Multiply by 13 and then by 6 to get rid of the denominators. You will have large coefficients to deal with, but I think that is less messy than fractions.
Once you have done that, substitute your value for x into each of the given expressions and see which is the smallest. Just guessing, but I suspect that 
is going to be the one.
John
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