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We cut a regular octagon ABCDEFGH out of a piece of cardboard.
If AB = 1, then what is the area of the octagon?
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Here is another way to solve the problem.
Let R be the radius of the circumscribed circle around our octagon.
Let's find its radius via the side length s.
The octagon consists of 8 congruent isosceles triangles, having
the common vertex in the center.
Each such a triangle is an isosceles triangle with the lateral sides of the length R
and the angle at the vertex of 45°. Write the cosine rule equation for such a triangle
= + - ,
= ,
= . (1)
In our case with s = 1, the last formula takes the form
= = = = = = . (2)
Now the area of one such a triangle is
= = = = = . (3)
For the area of the entire octagon, we should take the quantity (3) 8 (eight) times to get
= square units. ANSWER
Solved.