SOLUTION: An interior angle of a regular polygon is 160 degress. Find the sum of it's interior angles.

Question 1159975: An interior angle of a regular polygon is 160 degress. Find the sum of it's interior angles.
Found 3 solutions by MowMow, ikleyn, Alan3354:
Answer by MowMow(42)   (Show Source): You can put this solution on YOUR website!
The sum of all the degrees of the interior angles equals (n - 2)x180.
Then 160N = 180(N-2)
160N = 180N - 360
20N = 360
n = 18 sides
18x160 = 2880 degrees

Answer by ikleyn(52751)   (Show Source): You can put this solution on YOUR website!
.

Let "n" be the number of sides (= vertices). Then n*160 = (n-2)*180 degrees 160n = 180n - 360 360 = 180n - 160n 360 = 20n n = = 18. The sum of all interior angles = (18-2)*180 = 16*180 = 2880 degrees. ANSWER

Solved.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
An interior angle of a regular polygon is 160 degress. Find the sum of it's interior angles.
===============
Ext angles = 180 - 160 = 20 degs
360/20 = 18 sides.
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Sum = 180*(18-2) = 2880 degs
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PS it's = it is

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