SOLUTION: A regular hexagon (with all sides equal and all angles equal) has perimeter 60. Another regular hexagon has perimeter 180. What is the area of the smaller hexagon divided by the ar
Algebra.Com
Question 1149130: A regular hexagon (with all sides equal and all angles equal) has perimeter 60. Another regular hexagon has perimeter 180. What is the area of the smaller hexagon divided by the area of the larger hexagon, written as a fraction? (If the answer was one half, you would enter 1/2)
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A regular hexagon (with all sides equal and all angles equal)
--
No need to define "regular"
------
has perimeter 60. Another regular hexagon has perimeter 180.
========
What is the area of the smaller hexagon divided by the area of the larger hexagon, written as a fraction?
---
Perimeter is a function of the 1st power.
Area is a function of the 2nd power.
3 times the perimiter ---> 9 times the area.
-----
(If the answer was one half, you would enter 1/2)
No need to tell us how to enter fractions.
RELATED QUESTIONS
a regular hexagon is a six-sided figure with all six sides equal and all six angles... (answered by Jstrasner)
Problem: A regular hexagon is inscribed in a circle with a two-inch radius. What is the (answered by stanbon)
A regular hexagon has 5in sides and an apothem of 4.33in. Its perimeter is? Its area... (answered by robertb)
A regular hexagon (a 6 sided polygon with all sides and all angles equal) is inscribed in (answered by Alan3354)
in a regular polygon, all sides have the same length. suppose a regular hexagon has a... (answered by Alan3354)
A regular hexagon has a perimeter of 54cm. What is the area of this hexagon to the... (answered by robertb)
A regular hexagon ABCDEF has vertices at A(4,4√3), B(8,4√3), C(10,2√3), (answered by Alan3354)
What is the perimeter of a regular hexagon with sides 5.4 inches... (answered by vleith)
Please, I need help with the following problem regarding shapes and their sizes. Also... (answered by LinnW)