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If the lengths of the bases of an isosceles trapezoid are 10 cm and 22 cm, and if one of the legs is 10 cm,
then what is the length of the diagonal in cm?
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As posted, this text is nonsense.
I edited it in that unique way to make sense.
Hope you agree with my editing.
If so, then the solution is below.
Make a sketch.
Let ABCD be the given isosceles trapezoid.
The bases are AB = 22 cm long; CD = 10 cm;
the lateral sides are AD = BC = 10 cm.
Draw the perpendiculars CE and DF from the vertices C and D to the base AB.
It is clear that the right-angled triangles ADF and BCE are congruent.
Then the segments AF and BE have the length = = = 6 cm each.
The height of the trapezoid CE is the leg of the right angled triangle BCE and its length is equal to = = = 8 cm.
Now from the right-angled triangle AEC you have
AC = = = = = = = .
Thus the diagonal of the trapezoid AC is cm long. ANSWER
Solved. The answer is option B).