SOLUTION: Find the area of a regular hexagon with the given measurement. apothem = 2 radical 3

Algebra ->  Polygons -> SOLUTION: Find the area of a regular hexagon with the given measurement. apothem = 2 radical 3       Log On


   



Question 1118750: Find the area of a regular hexagon with the given measurement.
apothem = 2 radical 3

Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
hexagon and apothem....
Hexagon: Regular polygon with six congruent sides.
Apothem: Segment whose endpoints are center of a regular polygon and midpoint of one of the sides.

Draw the description! Can you identify one or two special right triangles which will help you from there?

I do not show a picture here but only describe one this much:
Hexagon is composed of six congruent equilateral triangles. If apothem a is the height, and one side is 2x, then the apothem cuts equilateral triangle into two special 30-60-90 right triangles, each also with leg x.

Your apothem, a is given but x can be solved for...
%282x%29%5E2=a%5E2%2Bx%5E2
Can you continue from here?

.
.
.
1 equilateral triangle area, %281%2F2%29%282x%29%2Aa=a%2Ax.
6 of these to make the hexagon area, 6%2Aa%2Ax.

Answer by ikleyn(52814) About Me  (Show Source):
You can put this solution on YOUR website!
.
The area of a regular hexagon is six times the area of central equilateral triangle.


You are given the apothem = 2%2Asqrt%283%29 of the regular hexagon, which is the altitude of the equilateral triangle.


Let x be the side length of the hexagon.

It is also the side length of the equilateral triangle.


In an equilateral triangle with the side length x the altitude is  x%2A%28sqrt%283%29%2F2%29%29.   //  Every student who study/studied Geometry must know it.


Therefore,  x%2A%28sqrt%283%29%2F2%29 = 2%2Asqrt%283%29,  which implies  x= 4.


Thus the side length of the regular hexagon is 4 units, same as the side length of the equilateral triangle.


Hence, the area of the equilateral triangle is  %281%2F2%29%2A4%2A%284%2Asqrt%283%29%2F2%29 = 4%2Asqrt%283%29 square units.


Then the area of the given hexagon is 6 times this value, i.e. 24%2Asqrt%283%29 square units.