SOLUTION: find the number of sides of a regular polygon whose interior angle is twice the exterior angle
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Question 1077097: find the number of sides of a regular polygon whose interior angle is twice the exterior angle
Found 2 solutions by 10037376, Alan3354:
Answer by 10037376(2) (Show Source): You can put this solution on YOUR website!
Let Interior Angle Be 2x
And Exterior Be x
Sum Of Angle Be 180 degrees
SOLUTION
2x+x=180
3x=180
x=60
;interior angle is 120 degrees
;exterior angle is 60 degrees
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
find the number of sides of a regular polygon whose interior angle is twice the exterior angle
--------
Int + Ext = 180
Int = 2*Ext
--> Ext angles = 60 degs
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The sum of exterior angles for ALL convex polygons is 360 degs.
360/60 = 6 sides.
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