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Polygon K has 3 more sides and 2015 more diagonals than polygon N. How many sides does each of these polygons have?
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The key to the solution is this statement:
The number of diagonals of the n-sided polygon is .
It gives you an equation
= 2015.
Simplify.
(n+3)*n - n*(n-3) = 2*2015,
n^2 + 3n - n^2 + 3n = 4030,
6n = 4030.
And since is not a whole number,
THE PROBLEM HAS NO SOLUTIONS.