SOLUTION: The area of an isosceles trapezoid is 45 cm2 and its height is 5 cm. Find the perimeter if one of the legs is 2/3 of the sum of the bases.

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Question 1028931: The area of an isosceles trapezoid is 45 cm2 and its height is 5 cm. Find the perimeter if one of the legs is 2/3 of the sum of the bases.
Answer by MathTherapy(10557)   (Show Source): You can put this solution on YOUR website!
The area of an isosceles trapezoid is 45 cm2 and its height is 5 cm. Find the perimeter if one of the legs is 2/3 of the sum of the bases.
Area = , where: , and h = height
------- Substituting 45 for area; and 5 for h (height)
---------- Dividing numerators by 5
----------- Cross-multiplying
Since one leg is the sum of the bases, then we can say that one leg (L) =
------- Substituting 18 for
L, or one of the legs = 12 units
Perimeter of isosceles trapezoid: = 18 + 2(12), or 18 + 24, or
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