SOLUTION: In a regular polygon, the exterior angle is one-eighth of an interior angle. How many sides has the polygon?

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Question 1012114: In a regular polygon, the exterior angle is one-eighth of an interior angle. How many sides has the polygon?
Found 3 solutions by Boreal, ikleyn, MathTherapy:
Answer by Boreal(15235)   (Show Source): You can put this solution on YOUR website!
{(n-2)/n}*180 is interior angle
exterior angle is 1/8 of that or {(n-2)/n}*22.5
The two add to 180
[180n-360]/n +[22.5n-45]/n=180
multiply by n
180n-360+22.5n-45=180n
22.5 n=405
n=18
18 sides

Answer by ikleyn(52778)   (Show Source): You can put this solution on YOUR website!
.
In a regular polygon, the exterior angle is one-eighth of an interior angle. How many sides has the polygon?
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First, let us find the interior angle.
Let x be the exterior angle. Then the interior angle is 8x.

Their sum is 180°. It gives you an equation

x + 8x = 180,   or   9x = 180,   or x =  = 20°.

Thus the interior angle  =  =  = 160°.

Now use the formula for the sum of interior angles of n-sided regular polygon.
It gives you an equation to determine n:

 = ,   or

n*160 = 180*(n-2).

Simplify and solve it:

160n = 180n - 360  ----->   20n = 360  ----->   n =  = 18.

Answer. n = 18.


Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

In a regular polygon, the exterior angle is one-eighth of an interior angle. How many sides has the polygon?
Let one of the exterior angles, be E
Then one of the interior angles = 8E
Since both sum to , we get: E + 8E = 180
9E = 180
E, or one of the exterior angles = , or
Since the sum of the exterior angles of a polygon is , and with one exterior
angle of the REGULAR polygon being , number of sides = , or
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