SOLUTION: Give the slope intercept form of the equation of the line that is perpendicular to 5x+2y=12 and contains the ponint (2,3).
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Question 998917: Give the slope intercept form of the equation of the line that is perpendicular to 5x+2y=12 and contains the ponint (2,3).
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
5 x + 2 y = 12
Find the slope of this line
2 y = -5 x + 12
Divide by 2
y = -2 1/ 2 x + 6
Compare this equation with y=mx+b, m= slope & b= y intercept
slope m = -2 1/2
The slope of a line perpendicular to the above line will be the negative reciprocal 2/5
Because m1*m2 =-1
The slope of the required line will be 2/5
m= 2/5 ,point ( 2 , 3 )
Find b by plugging the values of m & the point in
y=mx+b
3 = 4/ 5 + b
b= 11/5
m= 2/5
The required equation is y = 2/ 5 x + 11/ 5
m.ananth@hotmail.ca
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