SOLUTION: The midpoint of MN is point P at (–4, 6). If point M is at (8, –2), what are the coordinates of point N?
(–16, 14)
(–10, 5)
(2, 2)
(6, 2)
Algebra.Com
Question 989546: The midpoint of MN is point P at (–4, 6). If point M is at (8, –2), what are the coordinates of point N?
(–16, 14)
(–10, 5)
(2, 2)
(6, 2)
Found 2 solutions by solver91311, josmiceli:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Use the midpoint formulas. Substitute your values for
and then solve for
and
, the coordinates of the other endpoint.
and
John

My calculator said it, I believe it, that settles it
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
The x-coordinate of the midpoint is at:
where and are
x-coordinates of the endpoints
----------------------------------
The y-coordinate of the midpoint is at:
where and are
y-coordinates of the endpoints
----------------------------------
I will say that:
( x[1], y[1] ) = M( 8, -2 )
( x[p], y[p] ) = P( -4, 6 )
I need to find N( x[2], y[2] )
--------------------------
First, using:
--------------------
Next, using:
--------------------------------
The other endpoint is at: N( -16, 14 )
--------------------------------
check:
and
OK
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