SOLUTION: In my Geometry Book it says line GH has endpoints G(-3,2) and H(3,-2)
The question says find GH to the nearest tenth?
I don't understand how to do it please help me
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Question 986656: In my Geometry Book it says line GH has endpoints G(-3,2) and H(3,-2)
The question says find GH to the nearest tenth?
I don't understand how to do it please help me
Found 3 solutions by stanbon, mananth, josgarithmetic:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
In my Geometry Book it says line GH has endpoints G(-3,2) and H(3,-2)
The question says find GH to the nearest tenth?
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Formula for distance:: D = sqrt[(change in x)^2+(change in y)^2]
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Your Problem:
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D = sqrt[(3--3)^2 +(2--2)^2]
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D = sqrt[6^2 + 4^2]
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D = sqrt(36+16)
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D = sqrt(52)
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D = sqrt(4*13)
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D = 2sqrt(13)
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Cheers,
stan H.
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Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
G(-3,2) and H(3,-2)
(x1,y1) and (x2,y2)
distance formula
d=
Answer by josgarithmetic(39626) (Show Source): You can put this solution on YOUR website!
G and H form the hypotenuse of either of two right triangles. Look at the two points on a cartesian system. The third point may be either (-3,-2), or alternatively (3,2). Either choice, G, and H, and either of the third point form a RIGHT TRIANGLE. You can use Pythagorean Theorem formula to find length GH.
Taking the third point as T(-3,-2), your triangle has legs of lengths 4 and 6; look at the placements and coordinates of the points on your cartesian system for the plotted T, G, and H. The hypotenuse GH will be .
Look in your book if you want to see a derivation of the Distance Formula. It is essentially a form of the Pythagorean Theorem.
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