SOLUTION: The end points of AB are (2,3) and (8,1) the perpendicular bisector of AB is CD and point C lies on AB the length of CD is the square root of 10

Question 975942: The end points of AB are (2,3) and (8,1) the perpendicular bisector of AB is CD and point C lies on AB the length of CD is the square root of 10
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
This is correct.
The distance between the two points is the square root of the difference of the x s ^2 plus the square root of the difference of the ys ^2. The distance is square root of (40)= which is 2 square root of 10. Half the distance is the square root of 10. square root of 40=square root of (4*10).
The equation of the line through the points has slope -2/6 or -1/3
y-y1=(-1/3)((x-x1)
y-3= (-1/3) (x-2)
y= -(1/3)x +(2/3)+3 = -(1/3)x+11/3
perpendicular line has slope 3 (negative reciprocal)
goes through midpoint which is half the distance between the two points (5,2)
Its equation is y-2=3(x-5)
y=3x-13

RELATED QUESTIONS
Two points have coordinates A(2,3) and B(6,7).If C(7,t) lies on the perpendicular... (answered by Boreal)

Two points have coordinates A (2,3) and B (6,7). If C(7,t) lies on the perpendicular... (answered by josgarithmetic)

Use quadrilateral ABCD given that lines CD is the perpendicular bisector of lines AB and... (answered by greenestamps)

AB passes through the points (1, 3) and (3, 17). If CD is perpendicular to AB, what is... (answered by lwsshak3)

In triangle ABC, AB = 9, BC = 12, AC = 15, and CD is the angle bisector. Find the length... (answered by ikleyn,addingup)

A, B, C, and D are four points on a line such that AB : AC = 7 : 10 , and BD : CD = 9 :... (answered by greenestamps)

points A(3,4), B(-1,3), C (-2,-5) and D( a, -1) are the four points on a cartesian plane. (answered by mananth)

Line CD is 3 inches from one AB and CD and AB are parallel. Point K is in the line AB.... (answered by greenestamps,ikleyn)