SOLUTION: Let L denote the line passing through the point (6, 9) and the center of the circle (x - 4)2 + (y - 6)2 = 36. Find the slope of L. Decimal approximations will be marked incorrect

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Question 941934: Let L denote the line passing through the point (6, 9) and the center of the circle (x - 4)2 + (y - 6)2 = 36.
Find the slope of L. Decimal approximations will be marked incorrect.

Answer: 3/2
This is what I'm having trouble with:
Write an equation for L in terms of the variables x and y. Decimal approximations will be marked incorrect.
I'm not sure what it wants? I tried using the point-slope form as y=(3/2)(x-6)+9, but it said that was incorrect.

Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

the line passing through the point (, ) and the (,) of the circle
since we know that and (recall the circle formula )
so, we have two points the point (, ) and the point (, )
now find equation of a line passing through these two points:
Solved by pluggable solver: Find the equation of line going through points
hahaWe are trying to find equation of form y=ax+b, where a is slope, and b is intercept, which passes through points (x1, y1) = (6, 9) and (x2, y2) = (4, 6).
Slope a is .
Intercept is found from equation , or . From that,
intercept b is , or .

y=(1.5)x + (0)

Your graph:




since equation is which is ; so, the slope is

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