SOLUTION: I am trying to show the conjecture is false by finding a counterexample. The square of the sum of two numbers is equal to the sum of the squares of the two numbers. That is, (a+b

Algebra.Com
Question 92877: I am trying to show the conjecture is false by finding a counterexample.
The square of the sum of two numbers is equal to the sum of the squares of the two numbers. That is, (a+b)^2= a^2+b^2.
I have absolutely no clue of how to even begin to work this problem because I do not have a book, this is a workbook.

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
Is 2^2 + 3^2 equal to (2+3)^2 ?
Yes, if 4+9 = 25
But it doesn't.
-----------
That is called a "counterexample"
Cheers,
Stan H.

RELATED QUESTIONS

show the conjecture is false by finding a counterexample. the square of the sum of two (answered by bucky,richard1234)
Show the conjecture is false by finding a counterexample. The quotient of two whole... (answered by stanbon)
show the conjecture is false by finding a counterexample of... (answered by josgarithmetic)
the question is Show the conjecture is false by finding a counterexample the difference... (answered by edjones)
Yes, Hi. I need to show the conjecture is false by finding a counterexample in the... (answered by Positive_EV)
Show the conjecture is false by finding a counter example. The quotient of two whole... (answered by edjones)
please show the conjecture is false by coming up with a counterexample. the square... (answered by jim_thompson5910,stanbon)
Find one counterexample to show that this conjecture is false. The difference of two... (answered by rothauserc)
show that the conjecture is false by a counterexample. If a>b, then... (answered by ikleyn)