SOLUTION: Find the equation of the line through the given point and perpendicular to the given line. (0,0); -2x+4y=12

Question 911879: Find the equation of the line through the given point and perpendicular to the given line.
(0,0); -2x+4y=12
Found 2 solutions by stanbon, ewatrrr:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find the equation of the line through the given point and perpendicular to the given line.
(0,0);-2x+4y=12
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Given line -2x+4y = 12, find the slope::
4y = 2x + 12
y = (1/2)x + 3
slope = 1/2
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Slope you want must be -2.
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Form:: y = mx + b
Solve for "b" by substitution::
0 = (-2)*0 + b
b = 0
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Ans: y = -2x
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Cheers,
Stan H.
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Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
perpendicular to: -2x+4y=12 0r y = (1/2)x + 3, m = 1/2
New Line
m = -2 (Negative Reciprocal)
***Using point-slope form, P(0,0)
y = -2x
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