# SOLUTION: The length of a rectangular playing field is 5ft less than twice its width.If the perimeter of the playing field is 230ft,find the length and width of the field.

Algebra ->  Algebra  -> Points-lines-and-rays -> SOLUTION: The length of a rectangular playing field is 5ft less than twice its width.If the perimeter of the playing field is 230ft,find the length and width of the field.      Log On

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 Click here to see ALL problems on Points-lines-and-rays Question 88048: The length of a rectangular playing field is 5ft less than twice its width.If the perimeter of the playing field is 230ft,find the length and width of the field.Answer by SandySharma(35)   (Show Source): You can put this solution on YOUR website!Let the width of the field be x Length = 2x -5 Perimeter = x + x + 2x - 5 + 2x - 5 = 6x - 10 Given that perimeter = 230 ft. so, 4x - 10 = 230 Add 10 on both sides 6x = 230 + 10 6x = 240 Divide both sides by 6, you will get x = 240/6 = 40 length = 2x - 5 = 2*40 - 5 = 80 - 5 = 75 Answer: length = 75ft. & width = 40ft.