SOLUTION: the angle from the line through (-1,10) and (4,-7)to the line through (4,2) and (-1,-9) is 135.find y
Algebra.Com
Question 829839: the angle from the line through (-1,10) and (4,-7)to the line through (4,2) and (-1,-9) is 135.find y
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Find y for what? The intersection of the defined line? The angle is not needed for that.
First line, slope (-7-10)/(4-(-1))=-17/5
b=y-mx
b=-7-(-17/5)4=-7+68/5=6.6
y=-(17/5)x-3.6
Solve for x
5y=-17x-18
5y+18=-17x
x=-(5y+18)/17
Second line, slope (-9-2)/(-1-4)=11/5
b=y-mx
b=2-(11/5)4=2-44/5=-6.8
y=(11/5)x-6.8
Solve for x
y+6.8=(11/5)x
x=(5/11)(y+6.8)
The x expressions must equal at the intersection.
-(5y+18)/17=5(y+6.8)/11
-11(5y+18)=15*5(y+6.8)
-55y-18*11=5*15y+5*15*6.8
-55y-5*15y=15*5*6.8+18*11
y(55+5*15)=-(5*15*6.8+18*11)
130y=-708
y=-(708)/130
y=-5.446
Was that what you wanted?
RELATED QUESTIONS
The angle from the line through (-1,y) and (4,-7) to the line through (4,2) and (-1,-9)... (answered by Edwin McCravy)
find the angle from the line through (-5,9) and (10,-4) to the line through (-4,6) and... (answered by Solver92311)
Hi, Please help me...
The angle from the line through (1,y) and (4,-7) to the line... (answered by ikleyn)
The line passing through (-2,y) and (-4,4) is perpendicular to the line passing through... (answered by sudhanshu_kmr)
the line through (6, -4) and (-3, -2) is parallel to the line through (2, 1) and (0, y).... (answered by mananth)
find the tangent of the angle from the line through P(-5,9) and Q(10,-4) to the line... (answered by Alan3354)
Find the equation of the line that is perpendicular to the line in y=-1/4+2x and passes... (answered by Fombitz,ewatrrr)
write liner equations in slope-intercept form for each of the following:
1. Through(2,6) (answered by richwmiller)
the angle from the line through (x,-1) and (-3,-5) to the line through (2,-5) and (4,1)... (answered by robertb)