SOLUTION: IN THE GIVEN FIGURE AC MEETS CD AND AB AT POINT C AND A RESPECTIVELY,SUCH THAT ANGLE1+ANGLE2=90 DEGREE .PROVE THAT AB PARALLEL TO CD.
Algebra.Com
Question 760161: IN THE GIVEN FIGURE AC MEETS CD AND AB AT POINT C AND A RESPECTIVELY,SUCH THAT ANGLE1+ANGLE2=90 DEGREE .PROVE THAT AB PARALLEL TO CD.
Answer by tommyt3rd(5050) (Show Source): You can put this solution on YOUR website!
given figure...?
Please repost with a clear and complete question :)
RELATED QUESTIONS
Given AC=BD ._____.________________._____.
Prove AB=CD A B (answered by ikleyn)
A triangle ABC, where |AB| = |AC|, a line CD is drawn from angle C and intersects side AB (answered by CPhill,greenestamps,ikleyn,math_tutor2020)
The proof by indirect method is shown below. In which step does the contradiction appear?
(answered by solver91311)
A, B, C, and D are four points on a line such that AB : AC = 7 : 10 , and BD : CD = 9 :... (answered by greenestamps)
If a,b,c,d are in H.P., prove that ab+bc+cd =... (answered by Edwin McCravy)
Let A,B,C,D be collinear points such that AB = 2, AC = 3, AD = 4, BC = 5, BD = 6, CD = 1: (answered by greenestamps)
Given: B is between A and D
C is between A and D
Prove:... (answered by jim_thompson5910)
Given: B is between A and D;C is between A and D
Prove:... (answered by greenestamps)
I need help with my proofs. This problem i'm working on says,
given AB=CD
Prove AC=BD
(answered by J2R2R)