SOLUTION: write an equation in slope-intercept form for the line passing through points (0,3) and (-1,5)

Question 754179: write an equation in slope-intercept form for the line passing through points (0,3) and (-1,5)
Found 2 solutions by Alan3354, Cromlix:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
write an equation in slope-intercept form for the line passing through points (0,3) and (-1,5)
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find the slope = diffy/diffx = 2/(-1)
m = -2
(0,3) is the y-intercept
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y = -2x + 3

Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
gradient = y2 - y1/x2 - x1
= 5 - 3/-1 - 0
= 2/-1
= - 2
Using y - b = m(x - a) with m (gradient) = -2
and coordinates (-1,5)
y - 5 = -2(x -(-1))
y - 5 = -2x - 2
y = -2x - 2 + 5
y = -2x + 3
Hope this helps
:-)
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